Question

What is the value of (x + y)º? X + y ≠0​

Answer 1

Given :-

$\quad \leadsto \quad \sf x + y \neq 0$

To Find :-

Value of $\sf (x+y)^0$

Solution :-

Let's recall a identity ;

• $\sf \dfrac{a^m}{a^n} = a^{m-n}$

What if we put m = n ? Let's see ;

${ : \longmapsto \quad \sf \dfrac{a^m}{a^m}= a^{m-m}}$

${ : \longmapsto \quad \sf \cancel{\dfrac{a^m}{a^m}} = a^{0}}$

${ : \longmapsto \quad \therefore \quad \bf \quad a^0 = 1}$

But , it isn't possible if a = 0 , as $\bf 0^0$ is not defined (:

__________________________

Now here ,

If we put x + y = m , then we have ;

$\quad \leadsto \quad \sf m^0$

Now using above identity as $\bf x + y \neq 0$

${ : \implies \quad \bf \therefore \quad m^0 = ( x + y )^0 = 1 }$

Henceforth , The Required Answer is 1 :)