Question

what is the value of x + y÷x-y if x=4/6,y=6/4

Answer 1

Answer :


$given \: x \: = \frac{4}{6} \: and \: y \: = \frac{6}{4} \\ \\ = > \: to \: find \: the \: value \: of \: x + y \div x - y \: put \: the \: values \: of \: x \: and \: y \: in \: the \: given \: term \\ \\ we \: get \: - - \\ \\ = > \: \frac{4}{6} + \frac{6}{4} \div \frac{4}{6} - \frac{6}{4} \\ \\ = > \: firstly \: divide \: the \: fraction (to \: divide \: the \: fraction \: multiply \: by \: the \: reciprocal)\\ \\ = > \: \frac{4}{6} + \frac{6}{4} \times \frac{6}{4} - \frac{6}{4} \\ \\ = > \: reduce \: the \: fraction \\ \\ = > \: \frac{4}{6} + \frac{3}{2} \times \frac{3}{2} - \frac{6}{4} \\ \\ = > \: multiply \: the \: fractions \: \\ \\ = > \: \frac{4}{6} + \frac{9}{4} - \frac{6}{4} \\ \\ = > \: calculate \: the \: sum \: or \: difference \\ \\ = > \: \frac{17}{12}$


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Answer 2

$\underline{\bold{Given:-}}$

$x = \frac{4}{6} \: \: and \: \: y = \frac{6}{4}$

$\underline{\bold{To\:find:-}}$

$x + y \div x - y$

$\underline{\bold{Solution:-}}$

$x + y \div x - y$

$= \frac{4}{6} + \frac{6}{4} \div \frac{4}{6} - \frac{6}{4} \\ \\ = \frac{2}{3} + \frac{3}{2} \div \frac{2}{3} - \frac{3}{2} \\ \\ = \frac{2}{3} + \frac{3}{2} \times \frac{3}{2} - \frac{3}{2} \\ \\ = \frac{2}{3 }+ \frac{9}{4} - \frac{3}{2} \\\\LCM=12\\ \\ = \frac{8 + 27 - 18}{12} \\ \\ = \frac{35 - 18}{12} \\ \\ = \frac{17}{12}$

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