Question

What is the value of y? 3y^2 − 6 = 42

Answer 1

Answer:

$\fbox{\underline{\Huge{\texttt{4}}}}$

Step-by-step explanation:

$\text{Let's start by adding 6 to both sides of the equation to eliminate the -6.}$

$3y^2 = 48$

$\text{Next, let's divide both sides by 3 to eliminate the 3.}$

$y^2 = 16$

$\text{Find the square root of both sides.}$

$y = 4$

$\text{The value of y is }\bold{4}\text{.}$

Answer 2

Answer: 4

Step-by-step explanation:

3y^2 = 42 + 6

3y^2 = 48

y^2 = 48/3

y^2 = 16

Therefore:

y = 4 ( as 4 is the square of 16)

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