Question

What is the value of y in 2y + 1y + y3 + 2y + y3 = 1y8?

Answer 1

Thank you for this question. The solution is as below:

2y + 1y + y3 + 2y + y3 = 1y8

2y+1y+y3=1y8

2y+1y+y3-1y=8

5y=8

y=8/5

y=1.6

Hope this helps.

Answer 2

Answer: 4

Step-by-step explanation:

As the sum is even and two unit place of y3 and y3 giving even

Now the terms 2y , 1y and 2y the unit place cant be odd

because odd + odd+ odd is always odd

There using hit and trail method

22+12+23+22+23 = 102 ≠ 128  hence rejected

24+ 14+43+24+43= 148 Hence we accept the value

The greater number will given greater sum

Hence, the value of y is 4