Question

what is the valueof [sinA/cos A+cosA/sinA]×5sinA.cosA​

Answer 1

Answer:

hi friends

Step-by-step explanation:

according to question,

[tan A + cot A] x 5sin .cos

[ tan A + 1/tan A ] x 5 sin .cos

[tan^2 +1/tan ] x 5 sin.cos

[sec^2 /tan x 5 sin.cos

=> 1/cos^2 x cos/sin x 5 sin.cos

=> 5

5 is the sure answer

hope this answer is helpful

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Answer 2

Answer:

(sinA/cosA+cos A/sinA)5sinA.cosA

(sin^2A+cos^2A/sinA.cosA)5sinA.cosA

we know that

cos^2A+sin^2A=1

sin^2A=1-cos^2A

so

(1-cos^2+cos^2A/sinA.cosA)5sinA.cosA

(1/sinA cosA)5sinA.cosA

1*5=5