Question

What is the van't hoff factor which undergo tetramerization?

Answer 1

Answer:

In case of association i (van’t Hoff factor) is given by

i = 1 – (1- 1/n)α, where

n= number of molecules associates = 4 (here),

α = fraction of molecules associates

i = 1 – (1- ¼)α = 1 – ¾ α

if α be 1 (complete association), then

i= 1 – ¾ = ¼

Answer 2

Answer:

Answer:

Vant's hoff factor = Totalnumberofmolesafterdissociationtotalnumberofinitialmoles

K4[Fe(CN)6]=4K++[Fe(CN)6]4−

∴ vant's hoff factor = 5

Because total number of ions after dissociation is 5

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Explanation: