What is the vapor pressure above a solution prepared by dissolving 0.500 mol of a nonvolatile solute in 275 g of hexane (86.18 g/mol) at 49.6c? Phexane = 400.0 torr at 49.6c?
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9
Explanation:
Molar mass of hexane , C6H14 is = 6*12 + 14*1 = 86 g / mol No . of moles of hexane , n = mass / Molar mass = 275 g
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Answer:
The Vapor Pressure Of A Solution Prepared By Dissolving 0.500 Mol Of A Non-volatile Solute In 275 G Of Hexane (M = 86.18 G/mol) At 49.6 Degrees Celcius. P Hexane = 400.0 Torr @ 49.6 Degrees Celcius.
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