What is the vapor pressure of water if the pressure of dry oxygen gas is 32.2 bar?
Answers
Answered by
0
Explanation:
For O
2
gas collected over water, the pressure P=
V
nRT
P=
2 L
2 mol×0.08206 L⋅atm/mol⋅K×400 K
P=32.824 atm
Convert unit from atm to bar
P=32.824 atm×
1 atm
1.01325 bar
P=33.26 bar
The pressure of dry O
2
gas is 32.20 bar.
The vapour pressure of water =33.26 bar−32.20 bar=1.06 bar
Answered by
0
Explanation:
For O
2
gas collected over water, the pressure P=
V
nRT
P=
2 L
2 mol×0.08206 L⋅atm/mol⋅K×400 K
P=32.824 atm
Convert unit from atm to bar
P=32.824 atm×
1 atm
1.01325 bar
P=33.26 bar
The pressure of dry O
2
gas is 32.20 bar.
The vapour pressure of water =33.26 bar−32.20 bar=1.06 bar
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