Chemistry, asked by arvindbsavaj, 4 months ago

What is the vapor pressure of water if the pressure of dry oxygen gas is 32.2 bar?​

Answers

Answered by zebaalmaas786
0

Explanation:

For O

2

gas collected over water, the pressure P=

V

nRT

P=

2 L

2 mol×0.08206 L⋅atm/mol⋅K×400 K

P=32.824 atm

Convert unit from atm to bar

P=32.824 atm×

1 atm

1.01325 bar

P=33.26 bar

The pressure of dry O

2

gas is 32.20 bar.

The vapour pressure of water =33.26 bar−32.20 bar=1.06 bar

Answered by gracekumar765
0

Explanation:

For O

2

gas collected over water, the pressure P=

V

nRT

P=

2 L

2 mol×0.08206 L⋅atm/mol⋅K×400 K

P=32.824 atm

Convert unit from atm to bar

P=32.824 atm×

1 atm

1.01325 bar

P=33.26 bar

The pressure of dry O

2

gas is 32.20 bar.

The vapour pressure of water =33.26 bar−32.20 bar=1.06 bar

hope you understand it bro do hardwrok all the best

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