Math, asked by kinginimalu1578, 2 months ago

What is the variance if the first 9 multiples of 7

Answers

Answered by examreviewindia
0

Answer:

326.67

Step-by-step explanation:

see below link for detail calculation

Answered by rani78956
0

We must recall that:

A multiple in math are the numbers you get when you multiply a certain number by an integer.

Given: First 9 multiple of 7

7,14,21,28,35,42,49,56,63

Mean =\frac{SumOfObservation}{TotalNo.OfObservation}

=\frac{7+14+21+28+35+42+49+56+63}{9}\\

Mean \bar{x} =35

Finding variance:

\sum (x_i-\bar{x})^2=2940

Variance (\sigma)^2=\frac{\sum(x_i-\bar{x})^2}{n}=\frac{2940}{9}=326.66

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