Question

What is the velocity acquired by the body starting from rest having acceleration 20m/second square in 5s? *​

Answer 1

Given :

• Initial velocity, u = 0 m/s (as it is starting from rest)
• Time taken, t = 20 m/s²
• Acceleration, a = 5 seconds

To find :

• Final velocity, v

According to the question,

➞ v = u + at [ First equation of motion ]

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time taken

➞ Substituting the values,

➞ v = 0 + 20 × 5

➞ v = 0 + 100

➞ v = 100

• So, the final velocity is 100 m/s.

____________________

❖ Acceleration :-

Acceleration of a body can be defined as the rate of change of velocity with time is known as acceleration.

• SI unit of acceleration is m/s².
• Acceleration is vector quantity.

❖ Velocity :-

Velocity of a body is the distance travelled by per unit time in a given direction.

• SI unit of velocity is m/s.
• Velocity is vector quantity.

Answer 2

Answer:

Given :-

• Initial velocity = 0 m/s [ As it start from rest position]
• Acceleration = 20 m/s
• Time taken = 5 sec

To Find :-

Final velocity

Solution :-

As we know that

$\huge\tt \: V = U + AT$

This is the first equation of motion

$\tt \implies \: V = 0 + 20 \times 5$

$\tt \implies \: V = 0 + 100$

$\tt \implies \pink{\: V = 100 \: {ms}^{ - 1} }$

Extra information :-

First Equation of motion

V = U + AT

Second equation of motion

S = UT + ½ × at²

Third Equation of motion

V² - U² = 2as