What is the velocity at the lowest point of the circle , if the particle will leave a verticle circle of radius r
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Answer:
Let,
R= radius of circle
m= mass of particle
v= critical speed of particle
θ=60
0
Critical condition at C,
mg=
R
mv
2
v
2
=gR
v=
gR
Lets assume the speed of particle at point P is u
Applying conservation of energy,
2mgR+
2
1
mv
2
=
2
1
mu
2
+mgR(1+cosθ)
4gR+gR=u
2
+3gR
u
2
=2gR
u=
2gR
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