Question

what is the Velocity of a body if KE is twice it's momentum​

Answer 1

Answer:

The formula of the kinetic energy of the body is K.E. = 1/2 * m * v^2 while the formula for each momentum is p = m * v. Equating twice the momentum to K.E. results to 1/2 m* v^2 = 2 * m * v. Multiplying both sides by 2 we arrived at m * v^2 = 4 * m * v. Canceling m from both sides we get v^2 = 4 * v and dividing both sides by v we arrived at v = 4.

So the velocity of the body is 4 units to attain a K.E. that is twice in magnitude to its momentum.

This means that the body must move at 4 m/s to attain a kinetic energy that is twice in magnitude to its momentum.