Question

What is the velocity of a dropped object after it has fallen for 6.0s?

Answer 1

$\huge \bf \underline{ \underline \orange{answer : }} \:$

➔Initial velovity (u) = 0m/sec.

• As the object is dropped.

➔Final velocity (v) = ?

➔Time (t) = 6sec.

➔Acceleration = 10m/sec².

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By 1st Kinematical equation,

$\boxed{ \tt{v = u + at}}$

➣Putting values,

$\implies\tt{v = 0 + (10)(6)} \\ \\ \implies\tt \red{v =60 \frac{m}{sec} }$

Velocity after 6sec will be 60m/sec.

✪ More to know :-

➥2nd Kinematical equation

$\boxed{ \tt{s = ut + \frac{1}{2} a {t}^{2} }}$

➥3rd Kinematical equation

$\boxed{ \tt{ {v}^{2} = {u}^{2} + 2as}}$

Here,

• s = displacement.
• u = initial velocity.
• v = final velocity.
• t = time taken.
• a = acceleration.

Answer 2

Answer:

➔Initial velovity (u) = 0m/sec.

➔Initial velovity (u) = 0m/sec.As the object is dropped.

➔Initial velovity (u) = 0m/sec.As the object is dropped.➔Final velocity (v) = ?

➔Initial velovity (u) = 0m/sec.As the object is dropped.➔Final velocity (v) = ?➔Time (t) = 6sec.

➔Initial velovity (u) = 0m/sec.As the object is dropped.➔Final velocity (v) = ?➔Time (t) = 6sec.➔Acceleration = 10m/sec².

➔Initial velovity (u) = 0m/sec.As the object is dropped.➔Final velocity (v) = ?➔Time (t) = 6sec.➔Acceleration = 10m/sec².▬▬▬▬▬▬▬▬▬▬▬▬

➔Initial velovity (u) = 0m/sec.As the object is dropped.➔Final velocity (v) = ?➔Time (t) = 6sec.➔Acceleration = 10m/sec².▬▬▬▬▬▬▬▬▬▬▬▬By 1st Kinematical equation,