What is the velocity of a dropped object after it has fallen for 12 s? (-9.8m/s^2)
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Answer:
=acceleration due to gravity. HENCE VELOCITY AFTER 12 SECONDS OF THE OBJECT IS 120 M/S.
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g=acceleration due to gravity. HENCE VELOCITY AFTER 12 SECONDS OF THE OBJECT IS 120 M/S.
When air resistance is neglected, the velocity of the dropped object is equal to the product of the value of the acceleration due to gravity g which equals 9.8 m/s^2 and the elapsed time of 12 seconds. The formula used is v = g * t. In words, final velocity = elapsed time * g.
I will not show all the steps because of the condition you gave me. I resent being given conditions by people we are supposed to help without me receiving anything in return. Get your calculator and multiply 9.8 m/s^2 by 12 s. The unit of the product is m/s.
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When air resistance is neglected, the velocity of the dropped object is equal to the product of the value of the acceleration due to gravity g which equals 9.8 m/s^2 and the elapsed time of 12 seconds. The formula used is v = g * t. In words, final velocity = elapsed time * g.
I will not show all the steps because of the condition you gave me. I resent being given conditions by people we are supposed to help without me receiving anything in return. Get your calculator and multiply 9.8 m/s^2 by 12 s. The unit of the product is m/s.
62 views · Answer requested by Zentovo Business
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Hope it will help you
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