Physics, asked by aparnamenon2264, 2 months ago

what is the velocity of an shm?​

Answers

Answered by parthasarathidas78
1

Answer:

The velocity of the mass on a spring, oscillating in SHM, can be found by taking the derivative of the position equation: v(t)=dxdt=ddt(Acos(ωt+ϕ))=−Aωsin(ωt+ω)=−vmaxsin(ωt+ϕ). Because the sine function oscillates between –1 and +1, the maximum velocity is the amplitude times the angular frequency, vmax=Aω.

Answered by susmita2891
2

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The velocity of the mass on a spring, oscillating in SHM, can be found by taking the derivative of the position equation: v(t)=dxdt=ddt(Acos(ωt+ϕ))=−Aωsin(ωt+ω)=−vmaxsin(ωt+ϕ). Because the sine function oscillates between –1 and +1, the maximum velocity is the amplitude times the angular frequency, vmax=Aω.

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