Question

What is the velocity of the ball when it is 96 ft above the ground?

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

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s = ut - (1/2) g t² 
96 = 160 t - 16 t² 
16 t² - 160 t + 96 = 0 
t² - 10 t + 6 = 0 
t = [ 10 ± √ (100 - 24) ] / 2 
t = [ 10 ± √ (76) ] / 2 
t = 0.64 sec (on way up) 

v = ds/dt = 160 - 32 t 
v = 160 - 20.48 ft/s 
v = 140 ft/s (to nearest whole number)

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HOPE IT HELPS U.✌✌
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THANKS.❤❤

Answer 2

ANSWER:
The initial velocity is 0(if the particle is dropped).
The velocity at which it hits the ground is √2gh=>√2*9.8*96=1330.49ft/s.