Question

What is the velocity of the object for the graph shown below between 0sec to 2 sec and between 2sec and 5sec

Answer 1

Answer:

Magnitude of area under the v−t graph gives the distance travelled by the body.

For 0≤t≤4 s :

Displacement S 1

= Area = 21

×(20+40)×2+ 21

×(1+2)×20=90 m

For 4≤t≤5 s :

Displacement S 2

= Area = 21 ×1×20=10 m

Total distance d=S 1 +S2 =90+10=100 m

Option A is correct.means 80m

Answer 2

Answer:

where is the graph.. say the question clearly

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