What is the vertex of the graph of y=(x–3)2+4?
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Answer:
[3,4]
Step-by-step explanation:
y= [x-3]^2 +4
y - 4 = [x-3]^2
IF Y = X^2 is a parabola then vertex [0,0]
X=0 and Y=0
x-3 =0 and y-4=0
x=3 and ,y=4
vertex [3,4]
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