What is the vertex of the graph of y = x2 + 4x?
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a=1,b=−4. As a is positive, the parabola should open up.
As c=0, the parabola passes through the origin.
Vertex: x=−b/2a=2, so y=−4
⇒Vertex=(2,−4). Assuming two values of x,
x 1 0
y −3 0
Points obtained: (2,−4),(1,−3),(0,0).
Symmetry of parabola: Mirror image.
Points of (1,−3) and (0,0) are (3,−3) and (4,0), respectively.
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