What is the vertex of y=4 x²
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Given : y=4 x²
To find : Vertex
Solution:
If the equation of a parabola is in the form
y = ax² + bx + c
Then x vertex = -b/2a
comparing
y = 4x² with y = ax² + bx + c
a = 4 b = 0 c = 0
=> x vertex = -0/2(4) = 0
putting x = 0 in y = 4x²
=> y = 4(0)² = 0
(0 , 0) is the vertex of y = 4x²
other method
a vertex is a point of where the first derivative of curvature is zero.
y = 4x²
=> dy/dx = 8x
=> 8x = 0
=> x = 0
=> y = 0
(0 , 0) is the the vertex of y = 4x²
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