Physics, asked by pray6010, 1 year ago

What is the visible light intensity at the surface of the bulb?

Answers

Answered by Anonymous
0

Answer:

The equation needed is:

i =  \frac{p}{4\pi \: d {}^{2} }

Where P is the power of light emitted at the filament and d is the distance from filament to the surface of the bulb.

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