Physics, asked by TasneemG9810, 1 year ago

What is the voltage of a circuit carrying 2 amp of current through 36 ohms?

Answers

Answered by krishnagupta41

1

I=2A

R=36ohm

According to ohm's law

R=V/I

36=V/2

V=36×2

V=72V

Answered by tanishajaini

0

Answer: 72V

Explanation: I=2A

R=36 OHM

R=V/I

36=V/I

V=36×2

V=72V

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