Question

what is the volume at STP of 2.8 G of Nitrogen gas​

Answer 1

Answer:

The gas will occupy a volume of 2.24 L.

Explanation:

One mole of nitrogen gas occupies 22.4 L of volume.

So let us first find out the number of moles.......

So N2 = 2*14 = 28 g/mol.

So 2.8 g of N2 contains

(2.8 / 28 )moles = 0.1 mole.

So the gas will occupy a volume of 0.1 * 22.4 = 2.24 L of volume.

PLEASE MARK BRAINIEST

Answer 2

1 mole of nitrogen gas at stp=22.4l

mass of 1 mole of nitrogen =28g

so 2.8 g =0.1 mole

1 mole=22.4l

0.1 mole=22.4×0.1=2.24l

THEREFORE THE VOLUME AT STP OF NITROGEN GAS=2.24l