what is the volume at stp of 7.1 gm of chlorine
Answers
Answered by
9
molar mass of chlorine= Cl2 = 71g/mol
volume = mass × 22.7 l / molar mass
volume = 7.1g × 22.7 l / 71g
volume = 7.1×22.7 l /71
volume = 161.17 l /71
volume = 2.27 l
so 7.1 gram of chlorine contains 2.27 liter volume
_____________________________________
how we get formula,
volume = number of moles × 22.7
volume/22.7 = number of moles ______(1)
mass = number of moles × molar mass
mass/molar mass = number of moles _____(2)
volume/22.7 = mass/molar mass
volume = 22.7×mass/molar mass
___________________________
Basic information
• 1 mole of any substance contains 22.7 l volume at STP
• 1 mole of any substance contains Avogadro number of particles (atoms / moleculs)
• molecules = number of moles × 6.022×10^23 molecules
• atoms = atomicity × number of moles × 6.022 × 10^23 atoms
• mass = number of moles × molar mass
• volume = number of moles × 22.7
____________________________________
Rules of S.I units
1) If we express any physical quantities units in term of scientists name then we write all the letters in small letters if we only consider the first letter of it then we write in capital letters
ex : newton - N (not Newton)
2) no space between numerical value and unit
ex : 5m (not 5 m )
3) No comma and full stop after the unit
ex : 5N (not 5N, or 5N.)
4) S.I unit do not be take as plural it must always be in singular
ex :
5kg(not 5kgs)
10cm(not 10cms)
10 kilogram (not 10 a kilograms)
_______________________
please follow this rules
volume = mass × 22.7 l / molar mass
volume = 7.1g × 22.7 l / 71g
volume = 7.1×22.7 l /71
volume = 161.17 l /71
volume = 2.27 l
so 7.1 gram of chlorine contains 2.27 liter volume
_____________________________________
how we get formula,
volume = number of moles × 22.7
volume/22.7 = number of moles ______(1)
mass = number of moles × molar mass
mass/molar mass = number of moles _____(2)
volume/22.7 = mass/molar mass
volume = 22.7×mass/molar mass
___________________________
Basic information
• 1 mole of any substance contains 22.7 l volume at STP
• 1 mole of any substance contains Avogadro number of particles (atoms / moleculs)
• molecules = number of moles × 6.022×10^23 molecules
• atoms = atomicity × number of moles × 6.022 × 10^23 atoms
• mass = number of moles × molar mass
• volume = number of moles × 22.7
____________________________________
Rules of S.I units
1) If we express any physical quantities units in term of scientists name then we write all the letters in small letters if we only consider the first letter of it then we write in capital letters
ex : newton - N (not Newton)
2) no space between numerical value and unit
ex : 5m (not 5 m )
3) No comma and full stop after the unit
ex : 5N (not 5N, or 5N.)
4) S.I unit do not be take as plural it must always be in singular
ex :
5kg(not 5kgs)
10cm(not 10cms)
10 kilogram (not 10 a kilograms)
_______________________
please follow this rules
Answered by
0
Answer2.24 dm^3
Explanation:
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