Question

What is the volume in cm³ of 3.01×10²³ molecules of O2 gas at S.T.P? A 1000cm³
B 11000cm³
C 1120cm³
D 11200cm³

Answer 1

Answer:

(D) 11200 cm³

Explanation:

As we know, One mole of a gas at Standard Temperature and Pressure (STP) take the volume =22.4 L

And one mole of a gas contains 6.02* 10^23  molecules.

so the 6.02 *10^23 molecule will takes up the volume =22.4 L

Also the 1 molecule will takes up the the volume = 22.4 / 6.02*10^23

Hence the  3.01 *10^23  molecules will take up the volume

=(22.4/6.02*10^23 ) * 3.01*10^23

= 11.2 litre

Thus, 3,01*10^23 of oxygen will have the volume of 11.2 litre.

Convert liter in to cm^3 = 11.2*1000  = 11200 cm³

Hope it helps..!! ^_^