Question

what is the volume occupied by 10^24 molecules of n2

Answer 1

6.023 X 10²³ molecules of N2 occupies 22.4 litr. ( according to mole concept)

now 10 ^24 molecules occupy 22.4/6.023 X 10²³ (10^24)
3.71 x10¹= 37.1 Litr

Answer 2

The volume occupied by $10^{24}$ molecules of $(N_2)$ is 37.2 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number  of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text { avogadro's number}}=\frac{10^{24}}{6.023\times 10^{23}}=1.66moles$

1 mole of nitrogen $(N_2)$ occupies = 22.4 L

1.66 moles of nitrogen $(N_2)$ occupy= $\frac{22.4}{1}\times 1.66=37.2L$

The volume occupied by $10^{24}$ molecules of $(N_2)$ is 37.2 L

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