Question

what is the volume occupied by 24*10^24 molecules of co2​

Answer 1

We know that 1 mole of any ideal gas occupies 22.4 l (at NTP)

Thus 1 mol. = 22.4l

Given ;

no. of molecules = 24 × 10²⁴ molecules

let NA = 6 × 10²³ for approximate value

Thus no. of moles;

• n = N/NA
• n = 24 × 10²⁴/6×10²³
• n= 40 moles.

Thus by using unitary method;

1 mol. ----- 22.4l

40mol.---------x l

therefore;

• x = 40 × 224 ÷ 10
• x = 4 × 224
• x = 896 l

thus the given no. of molecules occupies 896 litres.

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