Question

what is the volume occupied by 30g of Neon gas at 400K and 0.821 bar ?​

Answer 1

Explanation:

Correct option is

B

42.43 L

According to the ideal gas law; PV=nRT

P = pressure; V = volume; n = no. of moles =

30

20

= 1.5 ; T = temperature and R = gas constant = 0.0821 Latmmol

−1

K

−1

Therefore V =

P

nRT

V =

(

760

750

)

1.5×0.0821×340

V = 42.43 L

Answer 2

42.43 l is the answer to the question.