Chemistry, asked by ugyentime88, 11 months ago

What is the volume occupied by 6.022 × 10^23 molecules of any gas at STP?

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Answered by TheWorker
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Answered by VineetaGara
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22.4 ml volume will be occupied by 6.022*10²³ molecules

This is a simple question based on the mole concept.

We know

The amount of substance that contains exactly 6.022*10²³ elementary entities is known as a mole.

The total mass of 1 mole of a substance is called molar mass.

For example molar mass of NaOH = 40

                      the molar mass of water = 18

The volume occupied by any gas at STP condition is known as molar volume.

Which is experimentally determined as equal to 22.4 mL

The standard Temperature Pressure condition (STP) is 273 K temperature and a pressure of 1 atm or 760 mm

From the above concept, it is clear that,

The volume occupied by 6.022 × 10^23 molecules of any gas at STP is 22.4 mL

#SPJ3

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