Question

What is the volume occupied by 8 gram equivalent weight of o2 at ntp?

Answer 1

Answer:

oxygen gas is O2 

oxygen gas is O2 It's molar mass is 32.00 g/mol 

moles O2 = mass / molar mass 

moles O2 = mass / molar mass = 4 g / 32 g/mol 

moles O2 = mass / molar mass = 4 g / 32 g/mol = 0.125 moles 

At STP 1 mole of any ideal gas occupies a volume of 22.4 L 

volume O2 = moles O2 x 22.4 L/mol 

volume O2 = moles O2 x 22.4 L/mol = 0.125 mol x 22.4 L/mol 

volume O2 = moles O2 x 22.4 L/mol = 0.125 mol x 22.4 L/mol = 2.8 L