What is the volume occupied by one ccl4 molecule at 20°C? Density of ccl4 is 1.6 gram/c3 at 20°C?
Answers
Answer:
We know that the number of chlorine atoms present in CCl4 is 4 atoms.
Since, 1 molecule contains 6.022 × 10^23 atoms.
For one mole of CCl4 it will contains 4 × 6.022 × 10^23 chlorine atoms.
As, the questions is asked for 1 CCl4 molecules.
So, now we can find the number of moles of CCl4 which will be as 1/(4*6.623*10^23) = 3.775 moles .
Hence, we know that weight of 3.775 moles will be 3.775*[12+4*35]=573.8 .
As the molar mass of CCl4 is (12 + 4*35).
So, as we know the density is 1.6g/cc the volume required = 573.8/1.6 =358.62L.
Hii Dear,
◆ Answer -
Volume = 1.6×10^-22 cm^3
● Explanation -
Mass of 1 CCl4 molecule would be -
Mass = Molar mass / Avogadro's number
Mass = 154 / 6.022×10^23
Mass = 2.56×10^-22 g
Volume of 1 CCl4 molecule will be -
Volume = mass / density
Volume = 2.56×10^-22 / 1.6
Volume = 1.6×10^-22 cm^3
Therefore, volume of 1 molecule of CCl4 is 1.6×10^-22 cm^3 at 20 ℃.
Thanks dear...