Chemistry, asked by aarbeepatel, 1 year ago

What is the volume occupied by one ccl4 molecule at 20°C? Density of ccl4 is 1.6 gram/c3 at 20°C?

Answers

Answered by AneesKakar
6

Answer:

We know that the number of chlorine atoms present in CCl4 is 4 atoms.

Since, 1 molecule contains 6.022 × 10^23 atoms.

For one mole of CCl4 it will contains 4 × 6.022 × 10^23 chlorine atoms.

As, the questions is asked for 1 CCl4 molecules.

So, now we can find the number of moles of CCl4 which will be as 1/(4*6.623*10^23) = 3.775 moles .

Hence, we know that weight of 3.775 moles will be 3.775*[12+4*35]=573.8 .

As the molar mass of CCl4 is (12 + 4*35).

So, as we know the density is 1.6g/cc the volume required = 573.8/1.6 =358.62L.

Answered by gadakhsanket
8

Hii Dear,

◆ Answer -

Volume = 1.6×10^-22 cm^3

● Explanation -

Mass of 1 CCl4 molecule would be -

Mass = Molar mass / Avogadro's number

Mass = 154 / 6.022×10^23

Mass = 2.56×10^-22 g

Volume of 1 CCl4 molecule will be -

Volume = mass / density

Volume = 2.56×10^-22 / 1.6

Volume = 1.6×10^-22 cm^3

Therefore, volume of 1 molecule of CCl4 is 1.6×10^-22 cm^3 at 20 ℃.

Thanks dear...

Similar questions