Question

what is the volume of 0.1 N dibasic acid sufficient to neutralize 1g of a base that furnishes 0.04 mole oh OH- in aqueous solution?

Answer 1

apply law of equivalence,

so, equivalence of acid = equivalence of base.

equivalence of acid = normality of acid × volume of acid = 0.1 × V

equivalence of base = normality of base × volume of base .

normality = molar concentration/n - factors

= 0.04/1 = 0.04 N

so, 0.1 × V = 0.04 × 1L

V = 400ml