Question

What is the volume of 0.1 N HCl required to react completely with 1.0 g of pure calcium carbonate (Ca = 40, C = 12 and O =16) BEST ANSWER GETS BRAINLIEST!!!​

Answer 1

Answer:

for complete reaction

the number of equivalents of the reactants must be same ...

so equivalents of HCl = equivalents of CaCO3 ...

Equivalents of HCl = N×V =0.1 × V

Equivalent of CaCO3 = Wt / equivalent wt = 1/50 ( eq. Wt = mol wt./ n- factor

= 100/2=50)

Hence , 0.1×V=0.02

therefore , V = 0.2 ltr or 200 ml.