Question

What is the volume of 0.1 N HCl required to react completely with 1.0 g of pure calcium carbonate (Ca = 40, C = 12 and O =16) BEST ANSWER GETS BRAINLIEST!!!​

Answer 1

Answer:

For complete reaction the number of equivalents of the reactants must be same ...so equivalents of HCl = equivalents of CaCO3 ........Equivalents of HCl = N×V =0.1 × V ......Equivalent of CaCO3 = Wt / equivalent wt = 1/50 ( eq. Wt = mol wt./ valency factor = 100/2=50).....Hence , 0.1×V=0.02 .....therefore , V = 0.2 ltr or 200 ml.....

Answer 2

Answer:

250cc

Explanation:

N×Vcc  = W                                  where E is equivalent wt. of CaCO3                                                                                                                                    

1000         E                                           E=40+12+16×3  = 50

                                                                           2

0.1 ×V =  1

1000       50

on solving

V = 250 cc