Question

What is the volume of 0.1 N HCl required to react completely with 1.0 g of pure calcium carbonate​

Answer 1

✿Given :-

N=0.1, w=1.0gm, Equivalent weight CaCo3 = 50, VHCl =?

✿ Solution :-

Using the law of equivalence:

Neq =N×V⇒V= Neq/N

V= w×1000 / EQ.Wt.×N = 1×1000/ 50×0.1 = 200cm3