Question

What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?
Use mc025-1.jpg and mc025-2.jpg.

Answer 1

Since it is state that the ideal gas we use ideal gas equation to solve the volume of this gas sample the ideal gas equation is expressed as

PV = nRT

V = nRT/P

V = 0.200(8.314) (400) / 200*10^3

V = 3.33×10^-3 m^3 or 3.33L

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Answer 2

Answer:

3.33L

Explanation: