Question

What is the volume of 10^21 molecules of oxygen at NTP

Answer 1

volume occupied by one mole of gas is 22.4 L

We know there are 6.022X1023 particles of a substance in one mole of that substance.

Thus. volume occupied by 6.022X1023 molecules of oxygen = 22.4 L.

volume occupied by 1 molecule of oxygen = 22.4(6.022X1023)

volume occupied by 1021 molecule of oxygen = 22.4(6.022X1023)×1021=13.4×103

Answer 2

Answer:

Hence,  the volume of  $10^{21}$ molecules of oxygen at NTP is $37.2cm^{3}$.

Explanation:

Concept:

What is NTP?

It is abbreviated as Normal Temperature and Pressure defined Normal temperature is 20 ℃ or 293.15 K or 68 ℉.

The National Institute of Standards and Technology introduced NTP (NIST). NTP defines 20 °C as the normal temperature. Compared to 0 °C, the standard temperature of STP, this temperature is more convenient and realistic in the real world. Numerous companies all across the world adopt NTP as a more usable standard.

Formula for NTP:

$V = \frac{nRT}{P}$

where, n = number of moles, R = gas constant, T = Temperature,

            P = Pressure.

Calculation:

6.022 x $10^{23}$ molecules of oxygen at NTP occupy = $22400cm^{3}$

So , $10^{21}$ molecules of oxygen at NTP occupy = $\frac{10^{21} }{6.022 * 10^{23} }$ x 22400

                                                                            = $37.2cm^{3}$

Therefore,  the volume of  $10^{21}$ molecules of oxygen at NTP is $37.2cm^{3}$.

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