Question

What is the volume of 23 g of neon gas at 1.0 °C and at a pressure of 2.0 atm?​

Answer 1

Answer:

The volume of neon gas is 990L.

Explanation:

To obtain the volume of neon gas, we will use the ideal law equation.

$PV=nRT$

Where.

1. P- Pressure
2. V- Volume
3. n- Moles
4. R- Ideal gas constant
5. T- Temperature (K)

The data given to us-

1. Pressure- 2 atm
2. Mass- 23 g
3. Temperature- 1°C = 274K
4. Ideal gas constant- 8.31 JK⁻¹mol⁻¹

First, we need to find the moles of neon gas by the mole formula.

$Moles= \frac{Mass}{Molar Mass}$

The molar mass of Neon - 20 g/mol

$Moles= \frac{20}{23}$

$Moles=0.87 mol$ of Neon gas

Now we can substitute the values in the ideal gas formula.

$2 *V = 0.87 * 8.31*274$

$2V= 1980\\V=\frac{1980}{2} \\V= 990 L$of Neon gas