What is the volume of 4.37 moles of an ideal gas at 29.5 c and 1.00 atm?
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Answered by
3
use the ideal gas equation
PV= nRT
then the volume is
V= nRT/P
therefore ,
V= (4.37 moles×0.0821 L.atm/K.mol ×302.65 k)/1.00 atm
v= 108.58L
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PV= nRT
then the volume is
V= nRT/P
therefore ,
V= (4.37 moles×0.0821 L.atm/K.mol ×302.65 k)/1.00 atm
v= 108.58L
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Answered by
0
17.6L...........
thanks
thanks
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