Question

what is the volume of 64 gram oxygen at sdp and its molecules mass is 32​

Answer 1

Answer:

Molecules mass =32

We know that,

1 Mole of O2=22.4 litres

32gm of O2=22.4/32 litres

64gm of O2 =22.4/32*64 litres

64gm of O2 = 44.8 litres

Explanation:

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Answer 2

$\huge\mathfrak{Solution:-}$

⭐ 1 mole of oxygen at STP = 22.4 litres

Molecular mass of oxygen = 32 g

Given mass = 64 g

Therefore, No of moles of oxygen = 64/32 = 2 moles

So, 2 moles of oxygen at STP will have 22.4 × 2

= 44.8 litres Answer.

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