What is the volume of 69.3g of nitrogen gas at stp?
Answers
Answered by
0
Assume the gas to be ideal,
Proper Method:
n= 69.3/28.
R=8.314.
At STP,
P=1 bar
T= 273.15 K
Therefore,
PV=nRT.
Solve and find V.
Shortcut:
Simply multiply the number of moles of gas by 22.7 to know the volume occupied by the gas at STP only.
Similar questions