Question

what is the volume of 6g of hydrogen at 1atm and 273°c ​

Answer 1

Answer:

V=pnRT=1. 53×0. 0821×546=89.

Hope it helps uh.....

Answer 2

Answer:

PV = nRT

First, find moles of hydrogen

6 g H2 x 1 mol/2g = 3 moles

PV = nRT

(1atm)(V) = (3mol)(0.0821L-atm/deg-mol)(273deg)

V = 67.2 L