Question

what is the volume of 79.3g of neon gas at stp?
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Answer 1

Answer:

according to ideal gas equation

Answer 2

The volume of the gas is 88.76 litres.

Given: 79.3g of neon gas.

To find: We have to find its volume at STP.

Solution:

According to ideal gas law-

PV=nRT

At STP and ideal conditions,

P is the pressure of the gas is equal to 1 atm.

V is the volume of the gas.

T is the temperature of the gas 273K.

The value of R is 0.082.

n is the number of moles.

The mass of neon gas is 79.3 grams.

The molar mass of neon is 20.

Thus the number of moles will be-

$\frac{79.3}{20} = 3.965$

Thus, the volume will be-

$v = \frac{3.965 \times 0.082 \times 273}{1} \\ v = 88.76$

The volume of the gas is 88.76 litres.