Question

What is the Volume of co2 obtained at STP by the complete decomposition of 9.85 g Na2CO3

Answer 1

Na2CO3 ⇒  Na2O + CO2
1 mole of sodium carbonate give 1 mole of carbon dioxide.
      105.98 g [M.W.] sodium carbonate gives 44.01 g [M.W.] carbon dioxide
     ∴  9.85 g sodium carbonate gives = ?                                                                                                               = 9.85 × 44.01                                                                                                        105.98                                                                           = 4.09 g of CO2
Moles of CO2 mole = weight      
                                Molar mass  
                             = 4.09     
                                44.01        
                            = 0. 092 mole

1 mole of gas = 22.4 L gas  
∴ 0.092 mole of CO2  = 22.4 × 0.092 = 2.06 L CO2 obtain  

Answer 2

Answer:

Zero Litres

Explanation:

On calculating this reaction, one might get answer 2.08 L but as Na2CO3 is soda Ash and it doesn't decompose at STP and this CO2 is not evolved. Therefore, 0 Litres.