what is the volume of Co2 produced at STP from 300 gram of calcium carbonate
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Answer:
67.2 L
Explanation:
CaCO3--->CaO + CO2
1 mole of CaCO3 produces 1 mole of CO2 =22.4 L CO2 at STP
so 300/100 = 3 moles of CaCO3 produces 3*22.4 L at STP = 67.2 L
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