Question

What is the volume of following at STP (1) 2g of H2, (ii) 16 g of O3.​

Answer 1

Answer:

1)1 mole of H2=2g

Hence volume at STP=22.4litres which is the molar volume.

2)48g=1 mole of O3

16g=(1/48)×16=1/3 moles

Volume at STP=(1/3)×22.4=7.39litres

Hope it helps

Answer 2

$hey Guys Here is your answer$

1.

$mole H2=2g$

$volume of STP=22.4 litre$

2.

$48g =1 mole of O3$

$16g=1/48 ×16$

$16g=1/3moles$

volume of STP=1/3*22.4

=7.39litre

✍️✍️ please mark it brainlist answer..