Question

What is the volume of gas at 2.00 atm and 200.0 K if its original volume was 300.0 L at 0.250 atm and 400.0 K

Answer 1

Answer:

Use combined gas law equation

P

1

V

1

T

1

=

P

2

V

2

T

2

V

2

=

P

1

V

1

T

1

×

T

2

P

2

V

2

=

1.00 atm × 22.4 L

273.15 K

×

200.0 K

2.00 atm

V

2

=

8.20

L