Question

What is the volume of N2O(g) formed at STP when 2 moles of each KOH and NO react as per following reaction?

2KOH + 4NO 2KNO2 + N2O + H2O


5.6 L


22.4 L


44.8 L


11.2 LWhat is the volume of N2O(g) formed at STP when 2 moles of each KOH and NO react as per following reaction?

2KOH + 4NO 2KNO2 + N2O + H2O


5.6 L


22.4 L


44.8 L


11.2 L

Answer 1

Answer:

11.2l

Explanation:

let us check which is the limiting reactant

KOH

2koh===>4NO

1koh===>2NO

2koh===>4NO

NO

4NO ====>2koh

1NO ====>1/2koh

2NO=====>1koh

so 2 koh react with 4NO

but we have only 2 moles of NO

so NO is the limiting reactant

after compelete usage of NO the reaction stops

4mol NO===>1mol N2O

1mol NO===>1/4mol N2O

2mol NO===>1/2mol N2O

1mol of a substance at STP will have a volume of 22.4l

1/2mol at stp will have

1/2×22.4=11.2l

Answer 2

Answer:

11.2 L (option D)

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