Question

What is the volume of N2O(g) formed at STP when 2 moles of each KOH and NO react as per following reaction?

2KOH + 4NO 2KNO2 + N2O + H2O


5.6 L


22.4 L


44.8 L


11.2 L

Answer 1

Answer:

22.4l

Explanation:

here dierectly without any calculation we can find liters of N2O formed

2KOH ,4NO=1MOL N2O

1 mol of a substance alwayas occupy 22.4l of space at STP

we can find it out this using ideal gas equation

pv=nrt

r=0.0821

find v

at stp volume changes according to no of moles of substance

at stp t=273k p=1atm no of moles =1molN2O

1×v=0.0821×1×273

v=22.4l