What is the volume of NH3 produced in the following reaction when 3.0 L of N2 reacts with 4.0 L of H2?
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hello mate
I just got the answer using the limiting reagent. Since nitrogen and hydrogen react in a 1 to 3 ratio, The hydrogen will be limiting (in order to react with 3 L of nitrogen, you would need 9 L of hydrogen, but you only have 4 L).
N2 + 3H2 ------> 2NH3
22.4L + 67.2L -----> 44.8L
SINce 66.2L hydrogen gives 44.8L NH3
SO 4L will give = 44.8 × 4 / 67.2 = 2.67L
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